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New soham

 #include <stdio.h> #include <stdlib.h> #define MAX 20 charstk[20]; int top = -1; int isEmpty(){ return top == -1; } int isFull(){ return top == MAX - 1; } char peek(){ return stk[top]; } char pop(){ if(isEmpty()) return -1; char ch = stk[top]; top--; return(ch); } void push(char oper){ if(isFull()) printf("Stack Full!!!!"); else{ top++; stk[top] = oper; } } int checkIfOperand(char ch) { return (ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'); } int precedence(char ch) { switch (ch) { case '+': case '-': return 1; case '*': case '/': return 2; case '^': return 3; } return -1; } int covertInfixToPostfix(char* expression) { int i, j; for (i = 0, j = -1; expression[i]; ++i) { if (checkIfOperand(expression[i])) expression[++j] = expression[i]; else if (expression[i] == '(') push(expression[i]); else if (expressi...
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Soham

 public class NumberTriangle {  public static void main(String[] args) {  int n = 5; // Number of rows in the triangle  for (int i = 1; i <= n; i++) { // Loop for each row  for (int j = 1; j <= i; j++) { // Loop to print numbers in each row  System.out.print(j + " ");  }  System.out.println(); // Move to the next line after printing each row  }  } } public class FactorialList {  public static void main(String[] args) {  int number = 1; // Start with the number 1 while (number <= 10) { // Loop through numbers from 1 to 10  int factorial = 1;  int i = number;  // Calculate factorial using a while loop  while (i > 0) {  factorial *= i;  i--;  }  // Print the factorial of the current number  System.out.println("Factorial of " + number + " = " + factorial);  number++; // Move to the next number  }  } } public class DivisionByZeroDemo {  p...
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SQL

 <!DOCTYPE> <html> <head>     <title>Fruit Cost Calculator</title>     <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />     <script type="text/javascript">     /* <![CDATA[ */         var total = 0.0;         function updateTotal(price, checkbox) {             if (checkbox.checked) {                 total += price;             } else {                 total -= price;             }             document.getElementById("runningTotal").value = total.toFixed(2);         }         function submitOrder() {             var taxRate = 0.05;             v...
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Soham

 [30/12, 10:34 pm] Soham BCA: DOCTYPE HTML>  <html> <head> <meta charset ="UTF-8"> <meta name ="viewport" content=" width=device-width, initial-scale=1.0"> <title> Department of MCA </title> </head> <body> <h1> VSM'S Institute of Technology </h1>  <hr> </hr> <h2> <em> MCA department</em></h2> <h3><small> <samp> Faculty details </samp> </small> </h3> <table border="1"> <tr>      <th>  Name </th>      <th> designation </th> </tr>     <tr>         <td> gayatri </td>         <td>HOD </td> </tr>     <tr>       <td> shraddha </td>       <td> professor</td> </tr> </table>   <h3><strong...
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Php

 1.prime   < html >     < style >         body {             background-color : lightblue ;                 }     </ style > <?php function isPrime ( $n ) {     if ( $n <= 1 )         return false ;     for ( $i = 2 ; $i <= sqrt ( $n ); $i ++)     {         if ( $n % $i == 0 )             return false ;     }     return true ; } $start = 3 ; $end = 20 ; $count = 0 ; for ( $i = $start ; $i <= $end ; $i ++) {     if ( isPrime ( $i ))     {         echo " $i \t " ;         $count ++;     } } echo " <br>The Total number of Prime numbers are = $count " ; ? > </ html > 2)Messgeg Passing    < html >     ...
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Abhijit_python

PART -A Program 1: Check whether the number is belongs to Fibonacci series or not. n=int(input("Enter a number:")) c=0 a=1 b=1 if n==0 or n==1: print("yes,It is Fibonacci Number") else: while c<n: c=a+b b=a a=c if c==n: print("Yes,{0} is fibonacci number".format(n)) else: print("No,{0} is not fibonacci number".format(n)) =========OUTPUT======== Ex:1 Enter a number:5 Yes,5 is fibonacci number Ex:2 Enter a number:4 No,4 is not fibonacci number   Program 2: Solve Quadratic Equations import cmath a=int(input("Enter value for a:")) b=int(input("Enter value for b:")) c=int(input("Enter value for c:")) d=(b**2)-(4*a*c) sol1=(-b-cmath.sqrt(d))/(2*a) sol2=(-b+cmath.sqrt(d))/(2*a) print("the solution are:\n",sol1,"and",sol2) =========OUTPUT======== Enter value for a:5 Enter value for b:10 Enter value for c:15 the solution are: (-1-1.4142135623730951j) and (-1+1.4142135623730951j)   Program 3:Find the sum...
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